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sunil kumar
· commented
· 1 Months ago
4/3
then think about he scenario when both are meeting.
let A by velocity 4x travelled distance 4Y.and B traveled 3Y.
NOW AS GIVEN ,SLOWER BUS,WHICH IS B; TOOK 16 hours in travelling 4y distance. so to travell 3x distance(which is before meeting) it takes 12 hrs(easily understood here) so total time+beore meeting +aft. meet=12+16=28
is easy,when we eliminate the written language of my explanation.