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Vinay Singh

· started a discussion

· 1 Months ago

vk (Question: 186651.0 )

sir 3rd line explain kar dijiye

Question:
In triangle ABC, DE || BC where and D is a point on AB and E is a point on AC. DE divides the area of ABC into two equal parts. Then DB : AB is equal to –
Options:
A) \(\sqrt{2}:(\sqrt{2}-1)\)
B) \((\sqrt{2}-1):\sqrt{2}\)
C) \((\sqrt{2}+1):\sqrt{2}\)
D) \(\sqrt{2}:(\sqrt{2}+1)\)
Solution:

Ans: (B) 


Knowledge Expert

· commented

· 1 Months ago

AD^2 / AB^2 = 1/2

(AD/AB)^2 = 1/2

AD/AB = 1/root2
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