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vivek

· started a discussion

· 1 Months ago

vivek (Question: 226475.0 )

here u apply wrong formula
replace sine22 with cos22

Question:
The value of  \(\cfrac{sin38^o-cos68^o}{cos68^o+sin38^o}\)    is equal to –
Options:
A) \(\sqrt[]{3} \ \ tan 8º\)
B) \(\sqrt[]{3} \ \ cot8º\)
C) \(\sqrt[]{3} \ \ sin 38º\)
D) \(\sqrt[]{3} \ \ sin 8º\)
Solution:
Ans: (a) 


Knowledge Expert

· commented

· 1 Months ago

Dear Student,

Its correct.....Cos68 = Cos(90-22) = Sin22.

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ravi

· commented

· 1 Months ago

its mistake.

rahul

· commented

· 1 Months ago

bhut mistake h yar
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