CLEAR
Toprankers-Info

+91 7676564400

Mobile App

Get it on Google Play
Discussions
Select Date
Tags:

Articles

Discussions
Submit Discussion
kundan jaiswal

· started a discussion

· 1 Months ago

video send (Question:108598.0)

video

Question:

A shopkeeper mixed 45 kg rice of cost Rs.10 per kg and some amount of other type of rice of cost Rs.15 per kg and sold the mixture at Rs.14 per kg. Thus, if he gained 5%, then the amount of other type of rice was:

Options:
A) 90 kg.
B) 15 kg.
C) 20 kg.
D) 30 kg.
Solution:
Ans: (a) Selling price of mixture = \(\unicode{x20B9} \) 14

Cost price of mixture = \(\unicode{x20B9}\cfrac{14}{1.05}\unicode{x20B9} = \cfrac{40}{3} \)

Let the amount of rice costing \(\unicode{x20B9} \)15 per kg = x kg

Rice 1                           Rice2

10                                 15

                 

                  40/3


15-40/3 =5/3              40/3-10 = 10/3


Quantity of First variety of Rice = 5/3 = 45

                                               1 = 45x3/5 = 27

therefore, quantity of second variety of Rice = 27x10/3 = 90kg

Knowledge Expert

· commented

· 1 Months ago

Dear student, Currently it is not available but we will look towards your issue. thanks for showing your interest. Keep learning, Team TR
-logo
We at aim to provide most comprehensive content & test for practice which is carefully divided into various chapters and topics to help you focus on your weak areas.Our Practice mock test gives you unmatched analytics to help you realize your strong areas,time management and improvement areas.Our Short & Crisp notes on each topic will help you to quickly revise the topic along with the tips & tricks of the exams.
More About
-Info
-Info

Mobile App

Get it on Google Play
About Us Campus Ambassador Careers Contact Us Refund Policy

All Rights Reserved Top Rankers

User Policy
Disclaimer
Terms & Conditions