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Pranay SB

· started a discussion

· 1 Months ago

Understandable way: (Question: 269918.0 )

Given answer is correct. Cross check with below provided soln.

Let m liters are taken out from 15 ltrs. So from that 40% acid and 60 % water is taken out; And, x ltrs are added to the acid.
Putting the above in the form of a formula:
(6-0.4m+m)/(9-0.6m)=1/1
Then m will be 2.5 ltrs

Question:

How many litres of a 15 litre mixture containing acid and water in the ratio 2 : 3 be replaced with pure acid so that the resultant mixture contains acid and water are in equal proportion?

Options:
A)

2 litre

B)

3 litre

C)

4 litre

D)

2.5 litre

Solution:

Ans: (d)

  

Pranay SB

· commented

· 1 Months ago

Sorry, not 'x', it is 'm'. Typing mistake.

Knowledge Expert

· commented

· 1 Months ago

Dear Student,
Good approach.
You can solve by this method also.

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