Online Courses
Explore
Offline Courses
-
LAW
-
Judiciary
-
Management UG
-
CAT & OMETs
-
CUET
-
Design
-
Architecture
-
UPSC Law Optional
Explore
Test Series
Explore
Resources
-
LAW UG (5 Year LLB)
-
LAW UG (3 Year LLB)
-
LLM + LAW Officer
-
Judiciary
-
Management UG
-
Management PG
-
Design & Arch.
-
NTA CUET [UG]
-
Career Counselling
-
Current Affairs
-
UPSC LAW
Explore
Join Us
Explore
Contact Us
Explore









Abhinav Sinha
· commented
· 1 Months ago
We have updated the solution,
please check.
For one digit number 1 × 9 = 9
(No. of single digit numbers are 9)
For two digit numbers 2 × 90 = 180
(No. of 2 digit numbers from 10 to 99 are 90)
For three digit numbers up to 500 = 3 × 401 = 1203
(No. of 3 digit numbers from 100 to 500 are 401)
Thus the required value = 9 + 180 + 1203= 1392.
Keep learning
Team TR