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Krishnendu Mondal

· started a discussion

· 1 Months ago

Try this! (Question: 108829.0 )

-12x + 12(3600-x) = 0

Question:

The cost price of two different types of watches is \(\unicode{x20B9} \)3600. On selling the first watch on 12% loss and second watch on 12% profit then there were no profit and no loss. What is the cost price of the first watch?

Options:
A) \(\unicode{x20B9} \)1680
B) \(\unicode{x20B9} \)2000
C) \(\unicode{x20B9} \)1800
D) \(\unicode{x20B9} \)2500
Solution:
Ans: (c) Let the CP of first watch be \(\unicode{x20B9} \)x.

\(\therefore\) The CP of second watch be \(\unicode{x20B9} \)3600 – x.

SP of first watch = \(\unicode{x20B9} \)0.88x

SP of second watch = \(\unicode{x20B9} \)1.12(3600 – x) 

A.T.Q.,

0.88x + 1.12(3600 – x) = 3600

\(\Rightarrow\) 0.88x – 1.12x = 3600 – 3600 × 1.12 

\(\Rightarrow\) 0.24x = 3600 × 0.12 \(\Rightarrow\) \(x=\unicode{x20B9} 1800 \)

RITESH RAJ

· commented

· 1 Months ago

Yet to be approved!

Knowledge Expert

· commented

· 1 Months ago

yes in this way we get the correct answer.. here er fixed its detailed solution.


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