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Ashish Pandey

· started a discussion

· 1 Months ago

tricks (Question:664500.0)

please provide tricky solution

Question:

If  x–y–18= –1 and x+y–32=1, then what is the value of 12xy(x2 –y2) ?  

Options:
A)

0

B)

1

C)

5122    

D)

6122    

Solution:

Ans: (d)


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