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Kumar Manish

· started a discussion

· 1 Months ago

trick (Question: 470999.0 )

any short trick of this type of question

Question:
The total cost price of two watches is \(\unicode{x20B9} \)840. One is sold at a profit of 16% and the other at a loss of 12%. There is no loss or gain in the whole transaction. The cost price of the watch on which the shopkeeper gains, is.
Options:
A) 360 
B) 370
C) 380 
D) 390
Solution:

C.P1. = x

C.P2. = 840 – x

P1% = 16%

S.P1 = \(\cfrac{116}{100}\) ×x 

S.P2 = \(\cfrac{88}{100}\)  × (840 – x)

S.P1+ S.P2 = 840 (as there is no profit or loss)

\(\cfrac{116x}{100}+\cfrac{73920-88x}{100}\)= 840       

73920 + 28x = 84000

28x = 84000 – 73920

28x = 10080

x = \(\cfrac{10080}{28}=360\)

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