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tomar

· started a discussion

· 1 Months ago

tomar (Question: 372488.0 )

plz solve

Question:

ABC is a triangle, right angled at B and D is a point on BC produced (BD > BC), such that BD = 2BC. Which one of the following is correct?

Options:
A)

AD2 = AC2 + 2AB2

B)

AD2 = AC2 + 3CD2

C)

AD2 = AC2 + 3AB2

D)

AC2 = AD2 + 3CD2

Solution:

Ans: (b)


tomar

· commented

· 1 Months ago

BD perpendicular khan h ....q m to nhi likha h ...ya y hota hi h ...koi fact h?

mrinal shastry

· commented

· 1 Months ago

AC^2=AB^2+BC^2 and AD^2=AB^2+BD^2,AD^2=AC^2-CD^2+4CD^2(BC=CD and BD=2CD),solve it and u will get the ans b
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