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hari om sharnam

· started a discussion

· 1 Months ago

this solution is wrong (Question: 114082.0 )

ABCQ is a parallelogram so AB=CQ
ABPC IS also a parallelogram so AB=PC
it means AB=PC=CQ
AB is half of PQ and AB || to PQ so by mid point theorem B & A is mid point of PR & AQ
hence PA is median

Question:
In the figure, AB || PQ, AC || PR and BC || QR, then AP is:


Options:
A) Perpendicular to QR
B)

The Area bisector of  ABPC

C) A median of \(\angle \)PQR
D) None of the above
Solution:

Here ABPC is a parallelogram, AP is the diagonal of ABPC. As, diagonal of a parallelogram  divides it into two congruent triangle. So, AP is the The Area bisector of  ABPC.

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