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Jitin Chittodiya

· started a discussion

· 1 Months ago

theorm glat apply kr di h. (Question: 390363.0 )

kse b krke ans nikal dia h

Question:

In the given figure, if PT is the tangent of circle, then what is the value of x?

  

Options:
A)

9 cm

B)

10 cm 

C)

12 cm

D)

16 cm

Solution:

Ans: (a)


\(PT^2 = PR \times RS \)

\((3\sqrt{5})^2 = (x-4) \times x\)

\(x^2 -4x-45 =0\)

(x-9) (x+5) =0

x =9 and x = -5 

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