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kvdinesh

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· 1 Months ago

surface area (Question: 246941.0 )

why should not we ignore surface area of all the given structures bases as they are closed inside we should minus total 4 Pi r squ

Question:
A machine is in the shape of a right circular cylinder with a hemisphere on one end and a cone on the other. The height of the cylindrical part is 3 times the radius. The radius of cylindrical part, hemisphere and conical part is equal and the ratio of height and radii is 4 : 3 in cone. If surface area of the Machine is 2175 cm2, then find the radius.
Options:
A) 8.5 cm.
B) 16 cm 
C) 14 cm 
D) 17 cm
Solution:

Ans: (a)


r2 = \(\cfrac{2175\times3}{29\pi}\)

= \(\cfrac{2175 \times3}{29\times22}\times7\)

= 72

r = 8.5 cm.

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