Discussions
Select Date
Tags:
Gourav

· started a discussion

· 1 Months ago

A trader sells two brands of petrol; one is Ordinary unleaded (OU) and other one is Super unleaded (SU). He mixes 12 liters of SU with 3 liters of OU and by selling this mixture at the price of SU he gets the profit of 9.09%. If the price of SU be ₹48 per liter, then the price of OU is:

Question:

A trader sells two brands of petrol; one is Ordinary unleaded (OU) and other one is Super unleaded (SU). He mixes 12 liters of SU with 3 liters of OU and by selling this mixture at the price of SU he gets the profit of 9.09%. If the price of SU be \(\unicode{x20B9} \)48 per liter, then the price of OU is:

Options:
A) \(\unicode{x20B9} \)38 per litre
B) \(\unicode{x20B9} \)42 per litre
C) \(\unicode{x20B9} \)28 per litre
D) \(\unicode{x20B9} \)35 per litre
Solution:

Ans(c)
\(CP=\cfrac{109.09}{100}=48\)


CP=\(\cfrac{48\times100}{109.09}\)=44



∴k = 44 – 16 = 28

Thus the price of  OU is Rs. 28/liter.

Knowledge Expert

· commented

· 1 Months ago

Dear student
We have updated the solution, kindly check it now.

Regards
Team TR

All Rights Reserved Top Rankers