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S.VIDHYA SHRI

· started a discussion

· 1 Months ago

speed (Question: 83313.0 )

how?

Question:

A is twice as fast as B and B is thrice as fast as C is. The journey covered by C in 3/2 hours will be covered by A in _____. 

Options:
A) 15 minutes
B) 20 minutes
C) 30 minutes
D) 1 hour
Solution:

Ans: (a)

Let x kmph be the speed of B. 

Let 2x kmph be the speed of A.

Speed of C = x/3  kmph

(Speed of A)/(Speed of C) = \(\frac{2x}{(\frac{x}{3})}\) = 6

Required time = \(\frac{(\frac{1}{6})}{(\frac{3}{2})}\)  hrs.

= \(\frac{1}{3}\times\frac{3}{2}\)=\(\frac{1}{4}\)  hrs. = 15 min.

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