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kavit

· started a discussion

· 1 Months ago

some problem in calculation (Question: 187992.0 )

TPQ is line so
∠PTR+∠QPR = 180, QPR=102
LET ∠PRS=x ,SO(PR=PS=QS) WE HAVE ∠QPS= x= ∠PRS
THERFOR ∠PRS=x= 102-X,
AND IN ∆PSR
∠PRS +∠PRS+∠PRS=180
x+x+102-x=180
SO x=78,
LEST PROVE IT
78+78+102-78=180

Question:


In the figure given above, PS = QS = PR, \(\angle \)TPR = 78°. \(\angle \)PRS is equal to — 
Options:
A) 45°
B) 50°
C) 52°
D) 55°
Solution:
Ans: (c)


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