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Mahesh Chandani

· started a discussion

· 1 Months ago

solving wrong (Question: 423162.0 )

41*3=123

Question:

  

Options:
A)

2799149    

B)

1492799    

C)

\(\frac{2938}{151}\)

D)

5

Solution:

Ans: (c)

\(x + \cfrac{2}{3+\cfrac{4}{5+\cfrac{6}{7}}}\) = 20

\(x + \cfrac{2}{3+\cfrac{7\times4}{41}}\) = 20

x + \(\cfrac{2\times41}{123+28}\) = 20

x = 20 - \(\cfrac{82}{151}\)

= \(\cfrac{3020-82}{151}\)

= \(\cfrac{2938}{151}\)

Knowledge Expert

· commented

· 1 Months ago

Dear Student,
We will fix both solution and answer
Sorry for the inconvenience.

Thanks and Regards
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