solution (Question:620632.0)

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Satendra Kumar

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solution (Question:620632.0)

solution ki 1st line m square root se phle 2 kaise aaya

Question:

Square root of $\frac{3}{2}$ (x – 1) + $\sqrt{{2 x}^{2} - 7 x - 4}$ is

Options:

$\frac{1}{2}$ $(\sqrt{2 x + 1} + \sqrt{x - 4})$

$\frac{1}{\sqrt{2}}$ $(\sqrt{2 x + 1} + \sqrt{x - 4})$

$\frac{1}{\sqrt{2}} (\sqrt{2 x - 1} + \sqrt{x + 4})$

$\frac{1}{2} (\sqrt{2 x - 1} + \sqrt{x + 4})$

Solution:

Ans: (b)

Given Expression = $\frac{1}{2}$ $\{(3 x - 3) + 2 \sqrt{(2 x + 1) (x - 4)}\}$

= $\frac{1}{2}$ $\{(2 x + 1) + (x - 4) + 2 \sqrt{(2 x + 1) (x - 4)}\}$

= $\frac{1}{2}$ ${(\sqrt{(2 x + 1)} + \sqrt{x - 4})}^{2}$

∴ Required square root = ± $\frac{1}{\sqrt{2}}$ $(\sqrt{2 x + 1} + \sqrt{x - 4})$

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solution (Question:620632.0)

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