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suresk kumar

· started a discussion

· 1 Months ago

solution (Question:444959.0)

give solution

Question:

  If 12 # 3 @ 2 = 38 and 14 @ 2 # 3 = 20, then 4 # 3 @ 1 = ? 

Options:
A)

 15

B)

 11

C)

 13

D)

 16

Solution:

 The pattern followed is as follows:-

12#3@2→12×3+2=3814@2#3→14+2×3=20Similarly,4#3@1→4×3+1=13   

Knowledge Expert

· commented

· 1 Months ago

Dear student,
Given answer is correct.kindly re-check the question and solution.

Regards
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