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ravindra

· started a discussion

· 1 Months ago

solution (Question: 364710.0 )

we know that foe the given number to be a multiple of 9,
(x+y) should be 5 or 14
so the possible pairs are,
(0,5),(5,0),(1,4),(4,1),(2,3),(3,2),(5,9),(9,5),(6,8),(8,6),(7,7)
so there could be 11 possible pairs of (x+y)

Question:

How many pairs of X and Y are possible in the number 763X4Y2, if the number is divisible by 9?

Options:
A)

8

B)

9

C)

10 

D)

11

Solution:

Ans:(d)

 

HIMANSHU JAISWAL

· commented

· 1 Months ago

Yet to be approved!
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