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Aditya Jha

· started a discussion

· 1 Months ago

solution (Question: 351236.0 )

ABCD is square and PQRSTUVW is octagon with equal sides constructed with in the square.

In order to have octagon with equal sides, we should have AP=QB=BR=SC=CT=….
Let AP=AW=x;
Let PQ = y; as all sides of octagon are equal, QR=RS=ST=TU=UV=VW=WP=y;
As the length of side of square is 2,
2x+y = 2 ------(1)
Applying Pythagoras to the right triangle APW, y2 = x2+x2 = 2x2
=> y= x√2 ------(2)
Solving (1) and (2):
2x+x√2 = 2 => x = 2/(2+√2) = √2/(√2+1)
=> y = x√2 = 2/(√2+1)

Question:

A square whose side is 2 metres, has its corners cut away so as to form an octagon with all its sides equal. Then, the length of the each side of the octagon, in metres is -

Options:
A)

22+1    

B)

22-1    

C)

22+1    

D)

22-1    

Solution:

Ans: (c)


OJASWI KOTHARI

· commented

· 1 Months ago

very nice

Yadvendra Yadav

· commented

· 1 Months ago

Thanks...

Knowledge Expert

· commented

· 1 Months ago

Dear Student,

yes this one also a detailed solution.

Keep learning keep solving
Best wishes
Team Toprankers

Puru Rajput

· commented

· 1 Months ago

kya faltu solution de raha hain bhai

PRATEEK

· commented

· 1 Months ago

Yet to be approved!
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