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SONU SINGH

· started a discussion

· 1 Months ago

solution (Question: 246837.0 )

not understand please give another solution

Question:

The area of a circle whose radius is 6 cm is trisected by two concentric circles. The radius of the smallest circle is –

Options:
A) \(2\sqrt{3}\) cm 
B) \(2\sqrt{6}\) cm
C) 2 cm 
D) 3 cm 
Solution:

Ans: (a)



PRAVIN KUMAR SINGH

· commented

· 1 Months ago

plz slove again in details

SUKH RAM

· commented

· 1 Months ago

a b c
area 1 : 2 : 3
radius 1 : root2 : root3

root3 = 6
1 = 6/root3 = 2root3

GAURAV KUMAR

· commented

· 1 Months ago

draw concentric circles with centre same as the circle of 6cm circle. let the radius of inner circle be r1 and middle cirlce be r2 and bigger circle is already 6cm. now (area of bigger circle - area of medium circle)=(area of medium - area of smaller)=area of smaller circle(condition for trisection)
now, pi(6^2-r2^2)=pi(r2^2-r1^2)=pi*r1^2.
when we solve it we get r1=2root3
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