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sutikshan babu

· started a discussion

· 1 Months ago

solution (Question: 246297.0 )

(k+1)(k+2)(k+3)........(k+10)
if we expand it you will find all term multiple of 'k' except 1*2*3*........*10
here 'k' is 8640
thus we can find remainder dividing 1*2*3*....*10 from 8640
ans will be 0

Question:
Find the remainder when the product of 10 consecutive natural numbers starting from 8641 is divided by 8640.
Options:
A) 3
B) 8639
C) 0
D) 55
Solution:

Ans: (c)

Required Remainder 


Knowledge Expert

· commented

· 1 Months ago

Dear Student,
You can solve a question by various method.
Our's one is also right.

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