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vinay kumar

· started a discussion

· 1 Months ago

solution (Question: 197117.0 )

how 13/2 came in the solution

Question:
If 3x = 9y = 27z and  \(\left ( \cfrac {1}{3x} + \cfrac{1}{6y} + \cfrac{1}{9z} \right ) = \cfrac{13}{2}\) , then find the value of z.
Options:
A) \(\cfrac{39}{2}\)
B) \(\cfrac{1}{39}\)
C) \(\cfrac{2}{39}\)
D) 1
Solution:
Ans: (c) 


TUSHAR DEY

· commented

· 1 Months ago

yes, exactly the solution is wrong
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