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vikash sangwan

· started a discussion

· 1 Months ago

solution (Question: 193814.0 )

if in question b{square}=ac is given then why we could not use it?

Question:
If a, b, c are three non-zero real numbers such that \(a + b + c = 0 \) and b2 = ca, then the value of  \(\cfrac{a^2+b^2+c^2}{b^2-ca}\)   is –
Options:
A) 3
B) 2
C) 0
D) 1
Solution:
Ans: (b) 


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