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vikash sangwan

· started a discussion

· 1 Months ago

how
angleA+angleC=180-135

Question:
If I is the incentre of ∆ABC and ∠BIC = 135º, then ∆ABC is –
Options:
A) acute angled 
B) equilateral 
C) right angled 
D) obtuse angled 
Solution:
Ans: (c)

The point where internal bisectors of angles of a triangle meet is called in-centre.

∠BIC = 135°
∴1/2 (∠B+∠C)=45°
⇒∠B+ ∠C=90°
∴ ∠A=90°

Knowledge Expert

· commented

· 1 Months ago

The point where internal bisectors of angles of a triangle meet is called in-centre.

∠BIC = 135°

∴1/2 (∠B+∠C)=45°

⇒∠B+ ∠C=90°

∴ ∠A=90°

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