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reddy

· started a discussion

· 1 Months ago

Solution (Question: 190273.0 )

For any question if u don't give solution especially in maths then what is the use of subscribing. Pls consider my request

Question:
A and B together can do a work in 12 days. B and C together can do it in 15 days. If A's efficiency is twice that of C, then the days required for B alone to finish the work is  –
Options:
A) 60 days
B) 30 days
C) 20 days
D) 15 days 
Solution:

Ans: (c)

Knowledge Expert

· commented

· 1 Months ago

Dear Student,

Thanks for the feedback, but as we see detailed explanation has been given. If still you didn’t get it please check alternate solution given below:

1/A' + 1/B' = 1/12
1/B' + 1/C' = 1/15
as A', B', C' here are the number of days and since A is twice the good worker then C therefore he will complete the job in half days. Therefore C' = 2*A'

1/A' - 1/C' = 1/60
1/C' = 1/2A'

Therefore A' = 30 days
B' = 20 days
C' = 60 days

Hope it helps you.
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