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vikash sangwan

· started a discussion

· 1 Months ago

solution (Question: 186897.0 )

reason.....how?

Question:
Which day was on 5 May, 1906 ?
Options:
A) Friday
B) Wednesday
C) Thursday
D) Saturday
Solution:
Ans: (d)

5th May, 1906 = (1905 years + Period from 1.1.1906 to 5.5.1905)


Odd days in 1600 years = 0


Odd days in 300 years = (5 x 3) = 15 = 1


Odd days in 5 years = 1 Leap year + 4 Ordinary years = 2 + 4 = 6


Jan - 31 days

Feb - 28 days

March - 31 days 

April - 30 days 

May - 5 days


Total days from 1.1.1906 to 5.5.1905 = 125 = 17 Complete weeks + 6 days


=> 17 weeks = 0 odd days


Total number of odd days = 1 + 6 + 6 = 13 = 1 week + 6 


So, 5th May, 1906 was Saturday.

Knowledge Expert

· commented

· 1 Months ago

5th May, 1906 = (1905 years + Period from 1.1.1906 to 5.5.1905)

Odd days in 1600 years = 0

Odd days in 300 years = (5 x 3) = 15 = 1

Odd days in 5 years = 1 Leap year + 4 Ordinary years = 2 + 4 = 6

Jan - 31 days
Feb - 28 days
March - 31 days
April - 30 days
May - 5 days

Total days from 1.1.1906 to 5.5.1905 = 125 = 17 Complete weeks + 6 days

=> 17 weeks = 0 odd days

Total number of odd days = 1 + 6 + 6 = 13 = 1 week + 6

So, 5th May, 1906 was Saturday.
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