CLEAR
Toprankers-Info

+91 7676564400

Mobile App

Get it on Google Play
Discussions
Select Date
Tags:

Articles

Discussions
Submit Discussion
anmol tyagi

· started a discussion

· 1 Months ago

solution (Question: 113285.0 )

Let total capacity be 30 ltrs
speed of A=3 ltrs/min and B=2 ltrs/min
time in which it should have been full without a leak =30/(3+2) = 6 mins
let the speed of pipe c be -x ltrs/min
so after leak being closed, the tank gets filled in 2 mins
A and B would fill in 2 mins=(3+2)x2= 10 litres
so, with the leak, in 6 mins, the tank was filled 20 ltrs(as 10 ltrs was filled afterwards of the total 30 ltrs)
so, 20/(3+2-x) =6mins. so x= 5/3 ltrs/mins
time taken by C alone= 30/(5/3) = 18 mins

Question:

One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 86 minutes, then the slower pipe alone will be able to fill the tank in

Options:
A) 144 min
B) 110 min
C) 80 min
D) 178 min  
Solution:
Ans: (a)

Let the slower pipe alone fill the tank in x minutes. Then, faster pipes will fill in x /3 minutes

Therefore, 1/x + 3/x = 1/36

4/x = 1/36

X = 144 min.

Knowledge Expert

· commented

· 1 Months ago

Dear student
Given answer is correct
we resolved it

Best wishes
Team TR
-logo
We at aim to provide most comprehensive content & test for practice which is carefully divided into various chapters and topics to help you focus on your weak areas.Our Practice mock test gives you unmatched analytics to help you realize your strong areas,time management and improvement areas.Our Short & Crisp notes on each topic will help you to quickly revise the topic along with the tips & tricks of the exams.
More About
-Info
-Info

Mobile App

Get it on Google Play
About Us Campus Ambassador Careers Contact Us Refund Policy

All Rights Reserved Top Rankers

User Policy
Disclaimer
Terms & Conditions