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Nikhil Manohar

· started a discussion

· 1 Months ago

Solution (Question: 108512.0 )

No of rounds by the larger wheel per min = 75
No of spokes passing at the junction = 75 x 30
So no of rounds by the smaller one = 75 x 30 ÷ 25
= 90
So no of rounds for 12 min
= 90 x 12 = 1080

Question:

Two wheels having gears moves in contact with each  other. The number of spokes in one wheel is 25 and on the other is 30. If the larger wheel moves 75 rounds per minute, then how many rounds the smaller wheel will move in 12 minutes?

Options:
A) 720
B) 1080
C) 360
D) 1200
Solution:
Ans: (b)

L.C.M. of 25 and 30 = 150

Round made by smaller wheel = \(\cfrac{150}{25}=6\)

Round made by larger wheel = \(\cfrac{150}{30}=5\)

Now, the number of rounds moved by smaller wheel per minutes  = \(\cfrac{6}{5}\times75=90\)

\(\therefore\) The number of rounds moved by smaller wheel in 12 minutes 

=  90 × 12 = 1080

Harsh Saini

· commented

· 1 Months ago

thanku buddy

Bikash Mohanty

· commented

· 1 Months ago

very good nikhil... simple explanation..

sanjib

· commented

· 1 Months ago

waah bhai tu knowledge expert ko fail kar dia hehe....

VIPIN

· commented

· 1 Months ago

Yet to be approved!

Somaiyya jawaid

· commented

· 1 Months ago

nice
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