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Karthik

· started a discussion

· 1 Months ago

Solution not convincing (Question: 186247.0 )

Solution not convincing, if

Question:
In \(\triangle\)ABC, \(\angle \)BAC = 90º and AB =\(\cfrac{1}{2}\) BC. Then the measure of \(\angle \)ACB is  –
Options:
A) 60º
B) 30º
C) 45º
D) 15º
Solution:
Ans: (b)


Knowledge Expert

· commented

· 1 Months ago

Its clearly given in the questions that AB=1/2 BC means AB/BC = 1/2

AB/BC = Cos(theta)

and cos60 measure 1/2

so, Cos(theta)=cos60=1/2

so, theta =60 = angle B

Now angle C = 180-90-60 = 30
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