Discussions
Select Date
Tags:
Shubham Vishwakarma

· started a discussion

· 1 Months ago

in steady flow it change in enthalpy
h1+q =h2 +w

Question:

In a steady flow reversible adiabatic process, work done is equal to:

Options:
A)

Change in internal energy

B)

Change in entropy

C)

Change in enthalpy

D)

Heat transferred

Solution:

Ans: (a)

All Rights Reserved Top Rankers