Solution is wrong (Question:257141.0)

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MANISH KUMAR CHOUDHARY

· started a discussion

· 1 Months ago

Solution is wrong (Question:257141.0)

Solution is not according to the question described. Correct answer as according to question wil be 2/(3)^(1/2)

DIVIYENDRA SINGH

· commented

· 1 Months ago

yes 2/(3)^1/2. kindly update the right solution

Meghna Midha

· commented

· 1 Months ago

Right ans

vishakha

· started a discussion

· 1 Months ago

solution is wrong (Question: 257141.0 )

in quesn angle PMS and PNS ARE 90 .

Question:

An isosceles triangle PQR is right angled at Q. S is a point inside the triangle PQR, M and N are the foot of the perpendiculars drawn from S on the sides PQ and PR respectively. If PM = 8 cm, PN = 6 cm and ∠QPS = 15°, sin75° = ?

Options:

$\frac{2}{2 \sqrt{3}}$

$\frac{4}{3}$

$\frac{3√3}{8}$

$\frac{8}{3 \sqrt{3}}$

Solution:

Ans: (c)

In ∆ PMS

Sin 75° = $\cfrac{PS}{8}$

And in ∆ PNS

Sin 60° = $\cfrac{PS}{6}$

PS = 6 × $\cfrac{√3}{2}$ = 3√3 cm

∴ sin75° = $\cfrac{PS}{8}$ = $\cfrac{3√3}{8}$

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