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lalit161090

· started a discussion

· 1 Months ago

solution incorrect (Question: 111705.0 )

area of hemisphere is 2pie*r*r so one can see only half part at a time so it should be pie r*r and please carefully use data u are using diameter not radius here

Question:
If a cylindrical tower D meter in diameter and H meter high is capped with a hemispherical dome, then the total visible surface of the tower will be:
Options:
A) \(\cfrac{\pi D}{2}\left ( 2H+\cfrac {D}{2} \right )\)
B) \(\cfrac{\pi D}{3}\left ( 2H+\cfrac {D}{2} \right )\)
C) \(\cfrac{\pi D}{3}\left ( 2H+D \right )\)
D) \(\cfrac{\pi D}{2}\left ( 2H+D \right )\)
Solution:
Ans: (d)

Total visible surface of tower

=  \(2\pi\times\cfrac{D}{2}\times H+ 2\pi \left ( \cfrac {D}{2} \right )^2\)         


\(=\pi DH+\cfrac{\pi D^2}{2}\)     


=\(\cfrac{\pi D}{2}\left [2H+D \right]\)               

                

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