CLEAR
Toprankers-Info

+91 7676564400

Mobile App

Get it on Google Play
Discussions
Select Date
Tags:

Articles

Discussions
Submit Discussion
aditya

· started a discussion

· 1 Months ago

soln (Question: 246954.0 )

when time increase and decrease in equal ration as here is given at one place 2 hours more and another 2 hour less than there is a direct formula to get speed ie

speed = [ 2*( increased speed)*(decreased speed)] /( increased - decreased speed)


=2 *(14)*(10)/ (14 -10) = 70km/hour


distance = speed *time

70* (Usual time) = (70 +14) (usual time -2)

70t = 84(t-2)
14t= 168 so t (usual time) = 12 hrs.

distance = speed * time
= 70 *12= 840 km.

isha mishra

· commented

· 1 Months ago

thanks! it was very useful

Knowledge Expert

· commented

· 1 Months ago

Dear Student,
You can also go with this approach, both are correct but we have provided general approach.

Thanks and Regards
Team TR
Sumit jain

· started a discussion

· 1 Months ago

Soln (Question:246954.0)

Can't understand

Question:
A train travels a certain distance with the uniform speed. If the speed of train is 14 km/h more, then the time taken to travel the same distance is 2 hour less. If the speed of train is 10 km/hr less, then time will be 2 hour more. Find the distance and the time taken to travel the distance.
Options:
A) 420 km, 12 hr 
B) 840 km, 8 hr 
C) 840 km, 12 hr 
D) Can’t be determined 
Solution:

Ans: (c)


-logo
We at aim to provide most comprehensive content & test for practice which is carefully divided into various chapters and topics to help you focus on your weak areas.Our Practice mock test gives you unmatched analytics to help you realize your strong areas,time management and improvement areas.Our Short & Crisp notes on each topic will help you to quickly revise the topic along with the tips & tricks of the exams.
More About
-Info
-Info

Mobile App

Get it on Google Play
About Us Campus Ambassador Careers Contact Us Refund Policy

All Rights Reserved Top Rankers

User Policy
Disclaimer
Terms & Conditions