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aditya

· started a discussion

· 1 Months ago

soln (Question: 246323.0 )

option a and b is elimenated as question is saying unit place should be 1 less than twice of ten's place.

by check option c we've to got 7 is 1 less than twice of 4 (ie 8)

74 - 47 = 27 as the question difference between new (74) and original (47) is 27

this difference (27) should be less than the original (47) ie 47 -27 =20

Question:
In a two digit number, the digit at the unit place is 1 less than twice the digit at the ten’s place. If the digit at unit’s and ten’s place are interchanged, the difference between the new and the original number is less than the original number by 20. The original number is – 
Options:
A) 57
B) 24
C) 47
D) 35
Solution:

Ans: (c)

Let ten’s digit = y, then unit digit = 2y – 1

\(\therefore\) original number = 10 y + (2y – 1) = 12y – 1

New number = 10(2y – 1) + y = 21y – 10 

then (21y – 10) – (12y – 1) = 12y – 1 – 20 

y = 4

original number = 12 × 4 – 1 = 47

CHUMKY JANA

· commented

· 1 Months ago

good solusion...

AMAR

· commented

· 1 Months ago

great
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