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Pramod Kumar Verma

· started a discussion

· 1 Months ago

soln (Question: 112266.0 )

20Au+20Ag=780+920
Au+Ag=85
Au+25=85
Au=60

Question:
A mass of gold and silver weighting 20 gram costs \(\unicode{x20B9} \)780. Had the weights of gold and silver are exchanged it would have cost \(\unicode{x20B9} \)920. Find the price of 1 gram of gold, if one gram of silver costs \(\unicode{x20B9} \)25.
Options:
A) \(\unicode{x20B9} \)25
B) \(\unicode{x20B9} \)40
C) \(\unicode{x20B9} \)50
D) \(\unicode{x20B9} \)60
Solution:
Ans: (d) Let the gold price of 1 gram =x

suppose y gram sliver and (20-y) gram gold

25y +x(20-y)=780

25y +20x-xy =780 -------- (1)

if the weight of gold sliver are interchanged

25(20-y)+xy =920

500-25y+xy =920

xy-25y =420 --------- (2)

add first equation and second equation

20x =1200

    x  = \(\frac{1200}{20}\) =   60

            

Pranay SB

· commented

· 1 Months ago

Very good bro!!

bharat bhushan

· commented

· 1 Months ago

nice trick thanx

bharat bhushan

· commented

· 1 Months ago

nice trick

Ankit Malik

· commented

· 1 Months ago

good
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