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aditya

· started a discussion

· 1 Months ago

soln (Question: 108755.0 )

think like tom is going 30 km/hrs at time 4:30 and john starts going in same direction 40 km/hrs at time 5:20 , now find out at what time john catches the tom.

a simple formula ( speed 1) * time difference/relative speed

(30 * 50) /10 = 150 minutes ie 2 hrs and 30 minute

as stated john starts 5:20 + 2:30 = 7:50 o clock

Question:

 Tom reads at an average rate of 30 pages per hour, while Jan reads at an average rate of 40 pages per hour. If Tom starts reading a novel at 4:30, and Jan begins reading an identical copy of the same book at 5:20, at what time will they be reading the same page? 

Options:
A) 9 : 30
B) 9 : 00
C) 8 : 40
D) 7 : 50
Solution:
Ans: (d) Lets say they met at page x. 
So time taken by Tom to read x pages = \(\frac{x}{30}\) hours 
So time taken by Jan to read x pages =\(\frac{x}{40}\)hours 
But the difference between their start is\(\frac{5}{6}\) hours 
So \(\frac{x}{30}\) - \(\frac{x}{40}\) = \(\frac{5}{6}\). 

 x = 100 
Jan will read 100 pages in 2:30 hours. So 5:20 + 2:30 = 7:50 

Preeti

· commented

· 1 Months ago

great job....

Knowledge Expert

· commented

· 1 Months ago

Dear Student,
Your answer is also right but our's one is a general approach

Thanks and Regards
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