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Awadhesh Ojha

· started a discussion

· 1 Months ago

sol (Question: 372520.0 )

let DE =X\nIN trianle BAC $BOP\nBO\/BA=OP\/AC\n(X+20)\/20=(X+40)\/36\nthen X=5\n\nNow in BDE $BOP\nX\/DE=(X+20)\/20\nPut x=5 and get DE \nAns 4

Question:

In the given figure, AC and DE are perpendicular to tangent CB. AB passes through centre O of the circle whose radius is 20 cm. If AC = 36 cm, what is the length (in cm) of DE?

  

Options:
A)

4

B)

6

C)

2

D)

8

Solution:

Ans: (a)


Awadhesh Ojha

· commented

· 1 Months ago

simple question
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