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Awadhesh Ojha

· started a discussion

· 1 Months ago

sol (Question: 372505.0 )

incentre is angle intersection point of angle bisector
so
tan30=r/3
r= root 3

Question:

A circle is inscribed in a triangle ∆ABC. It touches side AB at point X. If ∠A=60°, AX=3 cm, BX=5 cm, then find the radius of circle?

Options:
A)

  

B)

  

C)

  

D)

  

Solution:

Ans: (d)


Surender

· commented

· 1 Months ago

We take two triangles . They don't have same side but angle A took same in both triangle the by this trick how we find out the radius.

Surender

· commented

· 1 Months ago

Not possible. If we take triangles side diffrnt diffrnt. By this trick we always find same ans. How it possible

Abhishek Goyal

· commented

· 1 Months ago

great trick

NAVEEN KUMAR

· commented

· 1 Months ago

Yet to be approved!

NIHAR PRADHAN

· commented

· 1 Months ago

ok

Mohisin khan

· commented

· 1 Months ago

Yet to be approved!

Akshay Kapoor

· commented

· 1 Months ago

Dear Student
As you suggested that Incenter is a point which is equidistant from all the corners of the triangle, and also lies at the intersection of all the angular bisectors. If we consider angleA's bisector that gives us two sections of 30degre each. So tan30=r/3 so 1/root3=r/3
r=root3
Thanks and Regards
Team TopRankers

JITENDRA

· commented

· 1 Months ago

for real?

vivek

· commented

· 1 Months ago

Yet to be approved!

yatin kaushik

· commented

· 1 Months ago

Yet to be approved!

Tushar Rawat

· commented

· 1 Months ago

thanks
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