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Annu sharma

· started a discussion

· 1 Months ago

sol. (Question: 364648.0 )

yr....koi solution btao?

Question:

A man adds 500 ml of water to each litre of acid which is in a container. He sells 30 litre of mixture from container and adds 10 litre acid in the remaining. The ratio of acid and water in the final mixture is 11 : 5. Find the initial quantity of acid in the container. 

Options:
A)

120

B)

140

C)

100

D)

150

Solution:

Ans:(a)


harshit

· commented

· 1 Months ago

solution= acid =x ltr. watr= .5*x ltr
mixt=x+1.5x= 1.5x( acid :watr =2:1)
30 ltr mixture sold ie (30 ltr=20acid++10 watr)
left mixture= 1.5x-30(x ltr acid -20ltr acid + .5ltr watr-10ltr watr)
now 10 ltr acid added .so mixture=( (x-20 +10NEWADDED )acid+.(5ltr -10ltr) watr )
new ratio acid:watr =11:5
x-10/.5x-10 =11/5
solve and x=120.

Amit Yadav

· commented

· 1 Months ago

Yet to be approved!

Nitish kumar

· commented

· 1 Months ago

Yet to be approved!
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