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Nitin

· started a discussion

· 1 Months ago

give sol.

Question:
Which one of the following is not correct ?
Options:
A) (sec2q – 1)(1 – cosec2q) = – 1
B)

sin2q + cos2q = 1

C) \(\cfrac{sin\ \theta}{1+cos\ \theta}+\cfrac{1+cos\ \theta}{sin\ \theta}= \cfrac{2}{sin\ \theta}\)
D) cos2q – sin2q = cos q 
Solution:
cos2q – sin2q = cos q 

Knowledge Expert

· commented

· 1 Months ago

Hi apply trigonometric formula, only option(d) can not be proved.

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