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Karan Martin

· started a discussion

· 1 Months ago

sol (Question:113285.0)

Let pipe C alone can empty the cistern in x min.
A fills cistern in 1 min = 1/10;
B fills cistern in 1 min = 1/15;
A and B together fill in 1 min = (10*15)/(10+15) = 6 min
Since, waste pipe was left open for 6 min then,
6 min, 6/x part of cistern will be emptied by C.
Now,
6/x part of the cistern would be filled by A and B in 2 min.
Hence,
cistern will be filled in 3/x min. And
x/3 = 6
x = 18 min.

Baradi Manikanta

· started a discussion

· 1 Months ago

Sol (Question:113285.0)

(a+b)*2=c*6;
,(A+b)/c=3/1;
30/(5/3)=18

Question:

One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 86 minutes, then the slower pipe alone will be able to fill the tank in

Options:
A) 144 min
B) 110 min
C) 80 min
D) 178 min  
Solution:
Ans: (a)

Let the slower pipe alone fill the tank in x minutes. Then, faster pipes will fill in x /3 minutes

Therefore, 1/x + 3/x = 1/36

4/x = 1/36

X = 144 min.

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