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Gaurav

· started a discussion

· 1 Months ago

sol. (Question: 108022.0 )

let price=x
accn to ques, 300/x-300/x-10=5
x=30 so 300/30=10

Question:

A certain number of books were purchased for Rs.300. Five more books could have been purchased in the same amount if each book was cheaper by Rs.10. The number of books purchased was:

Options:
A) 20
B) 15
C) 10
D) 18
Solution:
Ans: (c)

Checking from option (c)

Let the number of books = 10

So, the price of one book = \(\unicode{x20B9} \)30

A.T.Q.,

If the price of one book = 30 – 10 = \(\unicode{x20B9} \)20

Then, the number of books =\(\cfrac{300}{20}=15\)

& the difference of books = 15 – 10 = 5

Dev

· commented

· 1 Months ago

It should be 300/x-10 -300/x=5

Dev

· commented

· 1 Months ago

Galt equation banaye ho bhai
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