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Deepak

· started a discussion

· 1 Months ago

sol dal do yaar. (Question: 113810.0 )

ye baat hai or itne comment aa rahe hai respond karlo. you people totally justify that you are purely indian, renowned for unprofessionalism. good work keep it up.

Question:

ABCD is a rhombus and O is the point of intersection of the diagonals AC and BD. The locus of a point which is equidistance from AB and AD is:

Options:
A) AC
B) BD
C) CB
D) CD
Solution:
Ans: (a)

Knowledge Expert

· commented

· 1 Months ago

Dear Student,

If ABCD is rhombus
Diagonals = AC and BD. and intersection of diagonals is O.

We get, Triangle ABO and ADO
In both triangle -
angle AOB and AOD = 90 because diagonals of rhombus are perpendicular to each other.
AO =AO common sides.
AB= AD sides of rhombus are equal.
By side angle side triangle AOB congruence of triangle ADO.
angle BAO = angle DAO. By correspondent angle of congruent

AC bisector of angle BAD.
thus required locus of AC which lies on the bisector of BAD which equidistant from AB and AD.


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