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smith

· started a discussion

· 1 Months ago

smith (Question: 108207.0 )

why OA/OC=OD/OB instead of OA/OC=OB/OD???

Question:
ABCD is a trapezium where AD||BC. The diagonals AC and BD intersect each other at the point O. If AO = 3, CO = x –3, BO = 3x –19 and DO = x – 5, then the value of x is:
Options:
A) 8, 9
B) –8, 9
C) 8, –9
D) –8, – 9
Solution:
Ans: (a)


According to the property of trapezium, 

\(\cfrac{3}{x-3}=\cfrac{x-5}{3x-19}\)

9x – 57 = x2 – 8x + 15

x2 – 17x + 72 = 0

x2 – 8x – 9x + 72 = 0

x = 8, 9

Vineet

· commented

· 1 Months ago

coz AD is parallel to BC , that would be the case if AB was parallel to CD
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