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Munagala Janardhana Reddy

· started a discussion

· 1 Months ago

simple way just remember after solving in proper procedure (Question: 246875.0 )

If R is of circle
perpendicular distance for center to chord is P
length of chord is be L
then the length of each tangents drawn from any point to the circle touches the extream points of chord is

==> (R*(L/2))/P
Ex1 : R = 5 L = 8 P= 3 ; ==> length of tangent = (5 *4/3) = 20/3
Ex1 : R = 5 L = 6 P= 4 ; ==> length of tangent = (5 *3/4) = 15/4
Ex1 : R = 13 L = 24 P= 5 ; ==> length of tangent = (13 *12/5) = 156/5
Ex1 : R = 13 L = 10 P= 12 ; ==> length of tangent = (13 *5/12) = 65/12

Question:
PQ is a chord of length 8 cm of a circle with centre O and of radius 5 cm. The tangents at P and Q intersect at a point T. The length of TQ is –
Options:
A) \(\cfrac{15}{4}\)
B) \(\cfrac{10}{3}\)
C) \(\cfrac{20}{3}\)
D) \(\cfrac{21}{4}\)
Solution:
Ans: (c)


isha mishra

· commented

· 1 Months ago

Thank you

MUKUL SAROHA

· commented

· 1 Months ago

Thnx Reddy bro

Sumit Sharma

· commented

· 1 Months ago

great
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