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SHUBHAM SHEKHAR

· started a discussion

· 1 Months ago

Shortcut solution (Question: 269916.0 )

Let total work be 60 units
then efficiency ---
P + Q = 4 units/day ------- (i)
also
30/ P + 30/Q = 40
P + Q = 4/3 * PQ
4 = 4/3*PQ
PQ = 3 --- --------- (ii)
from (i) and (ii), we get
P = 1 units /day
Q = 3 units/day
so, no. of days taken by P = total work / P's efficiency
= 60/1 = 60 hours

Question:

If P and Q can complete a work together in 15 hrs. However, P works alone and completes half the job and the Q completes the remaining half and work completes in 40 hrs. How long will P alone take to do the job if Q is more efficient than P?

Options:
A)

20 hrs

B)

30 hrs

C)

60 hrs

D)

40 hrs

Solution:

Ans: (a)

  

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