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Hardeep chahal

· started a discussion

· 1 Months ago

put x=0 and solve

Question:

If (x – 2a)(x – 4a)(x – 6a)(x – 8a) + ka4 is perfect square, then find the value of k?

Options:
A)

32

B)

16

C)

8

D)

10

Solution:

Ans:(b) 

  

Madhukar Gupta

· commented

· 1 Months ago

thanxx

Deepak Kumar

· commented

· 1 Months ago

But this concept does not hold in case (x-a)(x-2a)+ka2.

NISHANTH

· commented

· 1 Months ago

2*4*6*8=384 . so 16 should be added . 384+16 =400 ( a square number )

Ayush Agrawal

· commented

· 1 Months ago

How?

Knowledge Expert

· commented

· 1 Months ago

Dear student,
Given answer is correct
And your concept is also correct

Best wishes
Team TR

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