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pankaj punetha

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· 1 Months ago

there are no any short tricks ? its time taking question .

Question:
Three men A,B and C working together can do a job in 6 hours less time than A alone, in 1 hour less time than B alone and in one half the time needed by C when working alone. Then A can do the complete job in ?
Options:
A) 20/3
B) \(4\cfrac{2}{3}\)
C) \(5\cfrac{1}{3}\)
D) 10/3
Solution:

Ans: (a)

ATQ


x2 + 6x + x + 6 = 4x2 + 14x

4x2 - x2 + 14x - 6x - x - 6 = 0

3x2 + 7x - 6 = 0

x = -3 or 2/3

A = x + 6 = 2/3+ 6 =  \(\cfrac{2+18}{3}= \cfrac{20}{3}\) days

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